A middle aged male with some coronary risk factors presented to the ED after an episode of typical sounding chest pain that was resolved upon arrival.
He was in the ED for an hour when he developed chest pain again and had this ECG immediately recorded:
So the ECG is normal, right?
Some Background
What I neglected to tell you is that when the patient had arrived pain free, he had this ECG recorded:
Here there is subtle terminal T-wave inversion in V2, and a bit in V3, typical of early Pattern A Wellens' waves. |
See this case for Wellens' original images of Pattern A and Pattern B Wellens' waves.
So the first ECG is not normal; it is "pseudonormal."
It triggered the recording of serial ECGs (sorry, not available) which showed increasing ST elevation diagnostic of LAD occlusion.
So this was Wellens' syndrome, a state of spontaneous reperfusion of the LAD, manifesting with "reperfusion T-waves" and R-wave preservation after an episode of closure of the LAD. Thus, the patient presents pain free after an episode of angina.
The importance of Wellens' syndrome is that the artery can close off again at any moment, in which case the inverted T-waves will become upright again and look normal. This is called "pseudonormalization".
The first ECG was recorded so soon after re-occlusion of the artery that this ECG shows no signs of occlusion other than pseudonormalization, which requires comparison with the previous.
See these other cases of less subtle pseudonormalization (there are 7 cases here, the best are the last two)
- is a bit of neg. T wave in V2 in the first ECG ? (... yes)
ReplyDelete- Wellens's syndrome is allways interesting and practical
- thanks Dr Smith for sharing
Al
Al, in fact, no! It is not lower than the PQ junction.
DeleteSteve
Hi Steve,
ReplyDeleteI think what Alswiss (above) meant was there is an ever so slight terminal T-wave inversion on the 1st ECG in V2 & V3. (more so in V2) I actually noticed this prospectively, before scrolling down to the remainder of the case as I analyzed this first ECG. What do you think?
Another great case
Sam
Sam, I have considered that but when I look closely, the T-wave does not invert below the isoelectric line. Instead, it looks that way because, next, it turns up into a U-wave.
DeleteSteve